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esp32/mpthreadport: Use binary semaphore instead of mutex.

So a lock can be acquired on one Python thread and then released on
another.  A test for this is added.

Signed-off-by: Damien George <damien@micropython.org>
pull/7230/head
Damien George 4 years ago
parent
commit
864e4ecc47
  1. 5
      ports/esp32/mpthreadport.c
  2. 16
      tests/thread/thread_lock5.py

5
ports/esp32/mpthreadport.c

@ -192,7 +192,10 @@ void vPortCleanUpTCB(void *tcb) {
}
void mp_thread_mutex_init(mp_thread_mutex_t *mutex) {
mutex->handle = xSemaphoreCreateMutexStatic(&mutex->buffer);
// Need a binary semaphore so a lock can be acquired on one Python thread
// and then released on another.
mutex->handle = xSemaphoreCreateBinaryStatic(&mutex->buffer);
xSemaphoreGive(mutex->handle);
}
int mp_thread_mutex_lock(mp_thread_mutex_t *mutex, int wait) {

16
tests/thread/thread_lock5.py

@ -0,0 +1,16 @@
# test _thread lock objects where a lock is acquired/released by a different thread
import _thread
def thread_entry():
print("thread about to release lock")
lock.release()
lock = _thread.allocate_lock()
lock.acquire()
_thread.start_new_thread(thread_entry, ())
lock.acquire()
print("main has lock")
lock.release()
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