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51 lines
1.5 KiB
51 lines
1.5 KiB
From d06161b035dde4769199ad65aa0a587a5920012b Mon Sep 17 00:00:00 2001
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From: Darren Kenny <darren.kenny@oracle.com>
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Date: Fri, 22 Jan 2021 12:32:41 +0000
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Subject: [PATCH] kern/parser: Fix resource leak if argc == 0
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After processing the command-line yet arriving at the point where we are
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setting argv, we are allocating memory, even if argc == 0, which makes
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no sense since we never put anything into the allocated argv.
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The solution is to simply return that we've successfully processed the
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arguments but that argc == 0, and also ensure that argv is NULL when
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we're not allocating anything in it.
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There are only 2 callers of this function, and both are handling a zero
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value in argc assuming nothing is allocated in argv.
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Fixes: CID 96680
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Signed-off-by: Darren Kenny <darren.kenny@oracle.com>
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Reviewed-by: Daniel Kiper <daniel.kiper@oracle.com>
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Signed-off-by: Stefan Sørensen <stefan.sorensen@spectralink.com>
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---
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grub-core/kern/parser.c | 5 +++++
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1 file changed, 5 insertions(+)
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diff --git a/grub-core/kern/parser.c b/grub-core/kern/parser.c
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index 619db31..d1cf061 100644
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--- a/grub-core/kern/parser.c
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+++ b/grub-core/kern/parser.c
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@@ -146,6 +146,7 @@ grub_parser_split_cmdline (const char *cmdline,
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int i;
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*argc = 0;
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+ *argv = NULL;
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do
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{
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if (!rd || !*rd)
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@@ -207,6 +208,10 @@ grub_parser_split_cmdline (const char *cmdline,
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(*argc)++;
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}
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+ /* If there are no args, then we're done. */
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+ if (!*argc)
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+ return 0;
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+
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/* Reserve memory for the return values. */
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args = grub_malloc (bp - buffer);
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if (!args)
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--
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2.14.2
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